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 Unitary interpolation for operators in tridiagonal algebras Commun. Korean Math. Soc. 2002 Vol. 17, No. 3, 487-493 Printed September 1, 2002 Joo Ho Kang,Young Soo Jo Taegu University, Keimyung University Abstract : Given operators $X$ and $Y$ acting on a Hilbert space $\Cal H$, an interpolating operator is a bounded operator $A$ such that $AX=Y$. An interpolating operator for the $n$-operators satisfies the equation $AX_i=Y_i$, for $i=1,2,\cdots,n$. In this article, we obtained the following : Let $X = (x_{ij})$ and $Y =(y_{ij})$ be operators acting on $\Cal H$ such that $x_{i \sigma(i)} \neq 0$ for all $i$. Then the following statements are equivalent. \aligned \text{\rm (1)} & \ \text{\rm There exists a unitary operator A in Alg\Cal L such that AX =Y} \\ & \ \text{\rm and every E in \Cal L reduces A.} \\ \text{\rm (2)} & \ \text{\rm \displaystyle \sup \left\{ {{\| \sum_{i=1}^n E_i Y f_i\|} \over{\| \sum_{i=1}^n E_i X f_i\|}} : n \in N, E_i \in {\Cal L} \ \text{\rm and} \ f_i \in {\Cal H} \right\} < \infty and } \\ & \ \text{\rm {|y_{i \sigma(i)}| \over |x_{i \sigma(i)}|} = 1 for all i=1,2,\cdots.} \endaligned Keywords : interpolation problem, subspace lattice, unitary interpolation problem, Alg$\Cal L$ MSC numbers : 47L35 Downloads: Full-text PDF